If dy/dx=(1+x)/(xy) ,x > 0, and y =− 4 when x =1, when x =3, y =?

Question

6.433, -6.233

3.898, -3.898

4.711, -4.711

4.711 only

3.898 only

Answer 1

x y dy/dx = (1+x)
y dy = (1+x)dx/x = dx/x + dx

y^2/2 = ln x + x + c

I do not know what − 4 means so you take it from there. Put in y and x as given to get c
then do it for x =3