If D is the solid region in the first octant bounded above by the paraboloid z =
1 − x2 − y2 and below by the xy-plane, the volume of D is:
so i set this up integrating over dz dr dtheta and got pi/2 but the answer i spi/8
1 − x2 − y2 and below by the xy-plane, the volume of D is:
so i set this up integrating over dz dr dtheta and got pi/2 but the answer i spi/8