If current of 4.5A is used to find time taken for 5.5g of gold deposited. Given Au is 197 and 1 Faraday = 96500C

1 answer

To find the time taken for gold to be deposited, we can use Faraday's law of electrolysis, which states that the amount of substance deposited is directly proportional to the current and the time.

The formula to calculate the time taken is as follows:

Time (t) = (Mass of Substance (m) * Atomic Mass (M)) / (Current (I) * Faraday's Constant (F))

Given:
Current (I) = 4.5 A
Mass of gold (m) = 5.5 g
Atomic mass of gold (M) = 197 g/mol
Faraday's Constant (F) = 96500 C/mol

Plugging in the given values into the formula:

Time (t) = (5.5 g * 197 g/mol) / (4.5 A * 96500 C/mol)

Simplifying the expression:

Time (t) = (5.5 g * 197) / (4.5 * 96500)

Time (t) = 1.204 / 433.5

Time (t) ≈ 0.265 seconds

Therefore, the time taken for 5.5g of gold to be deposited with a current of 4.5A is approximately 0.265 seconds.