If cscØ = 4/3, find sinØ + sinØ cot^2 Ø

Answer 1

csc A = 4/3. sin A = 3/4,

x^2 + 9 = 16, X = sqrt7 = 7^(1/2).

Cot A = sqrt7/3.

sin A + sin A * cot^2 A = 3/4 + 3/4*(7^(1/2))^2 = 3/4+3/4*7 = 24/4 = 6.