If cotA=3/4find the value of 2sinA-3cosA ÷2sinA - 3cosA.

Answer 1

make a sketch of the triangle
cotA = 3/4 ---> x=3, y=4
by Pythagoras r = 5

now we can find all possible trig ratios
sinA = 4/5
cosA = 3/5

Once you establish the proper order of operation of your expression, just sub in the values

e.g. is it
2sinA-3cosA ÷(2sinA - 3cosA)
or
2sinA-(3cosA) ÷(2sinA) - 3cosA
or
2sinA-(3cosA ÷2)sinA - 3cosA , the way it would be according to BEDMAS