If cos25+sin25=k then the value os cos20 is ?

Answer 1

cos20 = cos(70-50) = cos70cos50 + sin70sin50

cos25+sin25 = √2 sin70 = k, so
sin70 = k/√2
cos70 = √(2-k^2) / √2

cos^2 25 + 2sin25cos25 + sin^2 25 = k^2
1 + sin50 = k^2
sin50 = k^2-1
cos50 = k√(2-k^2)

so, now we have

cos 20 = k√(2-k^2)√(2-k^2) / √2 + k(k^2-1)/√2
= (k(2-k^2) + k(k^2-1))/√2
= k/√2

Answer 2

Cos25°+sin25°=p cos50°=?