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If cos of theta= -7/12 and theta is in quadrant 2 then find

a. tan(theta) cot (theta)=
b. csc(theta) tan(theta)=
c. sin^2(theta)+ cos^2(theta)=

1 answer

cosθ = x/r, so

x = -7
r = 12
y = √95

Now, recall that
sinθ = y/r
tanθ = y/x

and let 'er rip.

(a) and (c) should require no calculation at all...

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