If CE = 29 and AC = 20, which of the following equations can be used to find AE?(2 points)

Question

Responses

202+292=x2
20 squared plus 29 squared is equal to x squared

20+x=29
20 plus x is equal to 29

202+x2=292
20 squared plus x squared is equal to 29 squared

20+29=x
20 plus 29 is equal to x
Question 3
Using the information given above, find AE. Round to the nearest tenth if necessary.(2 points)
AE =

Answer 1

To find AE, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the legs equals the square of the hypotenuse. Assuming AC is one leg (20 units) and CE is the other leg (29 units), the equation that fits this context is:

\[ 20^2 + x^2 = 29^2 \]

So, the appropriate equation to use is:

20² + x² = 29²

Now, let's solve for AE (x):

1. Substitute the values into the equation:

   \[ 20^2 + x^2 = 29^2 \]

   \[ 400 + x^2 = 841 \]

2. Rearrange to find x²:

   \[ x^2 = 841 - 400 \]

   \[ x^2 = 441 \]

3. Now, take the square root of both sides:

   \[ x = \sqrt{441} \]

   \[ x = 21 \]

Thus, rounded to the nearest tenth, AE is:

AE = 21.0