If carbon =62.07%,hydrogen=10.34%, and oxygen=27.59%. Determine its empirical formula, name each of them. Do not consider ones > 6-carbons.

1 answer

the % given is a % by mass. so they are grams.

convert the mass to mole for each element
divide each mole with the smallest mole
round off the moles to 1 sig figure.

then you can name them. the empirical formula is C3H6O. this formula can be an aldehyde and a ketone.