I assume you mean the angle between CxD and the plane of C and D.
CxD = 48i+j-82k
Since CxD = |C||D|sinθ,
sinθ = 95.0211/(8.3666*11.3578) = .9999
θ = 89.4°
If C= -5j + 6j - 3k and
D= 7i + 8j + 4k are vectors, find:
The cross product and its respectively angle
2 answers
ignore my comment. the angle between C and D is found.