Solve the problem just like the example below
⬇️
If C, equals, 3, x, squared, plus, 4, x
C=3x
2
+4x and
B, equals, 2, x, squared, minus, 7, comma
B=2x
2
−7, find an expression that equals
2, C, plus, 2, B
2C+2B in standard form.
C, equals, 3, x, squared, plus, 4, x
C=
3x
2
+4x
B, equals, 2, x, squared, minus, 7
B=
2x
2
−7
2, C, plus, 2, B
2C+2B
2, left parenthesis, 3, x, squared, plus, 4, x, right parenthesis, plus, 2, left parenthesis, 2, x, squared, minus, 7, right parenthesis
2(3x
2
+4x)+2(2x
2
−7)
6, x, squared, plus, 8, x, plus, 4, x, squared, minus, 14
6x
2
+8x+4x
2
−14
10, x, squared, plus, 8, x, minus, 14
10x
2
+8x−14
1 answer
Let's solve for \(2B + 3A\) using the definitions provided:
Now we need to calculate \(2B + 3A\):
\[ 2B + 3A = 2(w + 1) + 3(2w + 1) \]
Now, let’s expand both terms:
\[ 2(w + 1) = 2w + 2 \] \[ 3(2w + 1) = 6w + 3 \]
Now we can combine these results:
\[ 2B + 3A = (2w + 2) + (6w + 3) \] \[ = 2w + 6w + 2 + 3 \] \[ = 8w + 5 \]
Therefore, the expression \(2B + 3A\) in standard form is:
\[ \boxed{8w + 5} \]
