If at noon today someone has 1 E. coli cell, in their gut/large intestine, and E. Coli does binary fission, in unison each thirty minutes, how many will one have in their gut at 11:55 A.M. tomorrow? (five minutes short of a whole day)
I'm confused on how to begin setting this up. I saw an example of a problem similar to this one, and it said N=the initial count of how many E. Coli were in the stomach the first time, multiplied by the number of hours it was in the stomach, which in this case would be 23.5hrs. So, would I set it up like N=1(2^23.5)? If not could you help me set it up correctly? I don't believe this is the right way because my answer comes out to 552.25, which seems like less than I would believe to be in the stomach after all of that time, but maybe not? Please help asap! Thank You!
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