since v=0,
h = -16t^2 + 200
0 = -16t^2 + 200
t = 3.54
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s (where h and s are in ft, t is in seconds and v is in ft/sec) If a rock is dropped from the top of a 200 ft building, solve for the time that it takes for it to hit the ground(when h=0) Hint: Initial velocity when dropped is 0. Round your answer to 2 decimals. Enter: seconds
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1 answer