If an arrow is shot upward on the moon with a velocity of 56 m/s, its height in meters after t seconds is given by . Find the instantaneous velocity after one second.
4 answers
Please walk me through each step
Sorry forgot to give you the equation
its heigh in meters after t seconds is given by
h=56t-0.41t^2
its heigh in meters after t seconds is given by
h=56t-0.41t^2
Since you labeled it Calculus, ....
dh/dt =56 - .82t
when t = 1
dh/dt = 56 - .82(1)
=55.18 m/s
dh/dt =56 - .82t
when t = 1
dh/dt = 56 - .82(1)
=55.18 m/s
Thanks ur amaizing!