If an arrow is shot into the air at a speed of 64 feet per second from a platform that is 30' high. The height of the arrow is given by the function h(t)= -16t2 + 64t + 30, where t is time in seconds. What is the maximum height of the arrow?

Question

If an arrow is shot into the air at a speed of 64 feet per second from a platform that is 30' high.  The height of the arrow is given by the function h(t)= -16t2 + 64t + 30, where t is time in seconds.  What is the maximum height of the arrow?

R_scott · Answer

the maximum lies on the axis of symmetry of the parabola tmax = -b / 2a = -64 / (2 * -16) find tmax , plug into the equation to find max height