If alpha and beta are zeroes of 4x-5x-1. Find the value of alpha square multiplied by beta
2 answers
Given equation is 4x2-5x-1,now a+b=-(-5)/4=a=5-4a/4 again a.b=-1/4 put the value of a we get a=1,and b=1/4 so a2b=1/4.
Assuming you mean:
4x^2 - 5x - 1 = 0
x = (5 ± √41)/8
so alpha = (5+√41)/8 and beta = (5-√41)/8
a^2b = (5+√41)/8 * (5+√41)/8 * (5-√41)/8
= (5+√41)/8 * (25 - 41)/64
= (5+√41)/8 * (-16/64)
= (-5-√41)/32
GAURAV concluded that a = 1, b = 1/4
but those are not the zeros of the given equation.
my answer can be verified with a calculator.
4x^2 - 5x - 1 = 0
x = (5 ± √41)/8
so alpha = (5+√41)/8 and beta = (5-√41)/8
a^2b = (5+√41)/8 * (5+√41)/8 * (5-√41)/8
= (5+√41)/8 * (25 - 41)/64
= (5+√41)/8 * (-16/64)
= (-5-√41)/32
GAURAV concluded that a = 1, b = 1/4
but those are not the zeros of the given equation.
my answer can be verified with a calculator.
1 answer