If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

9 answers

We know that (a+b)^2
= a^2 + 2ab + b^2
= ...
ab = 8, a^2 + b^2 = 16.

(a + b)^2 = a^2 + 2ab + b^2 =
(a^2 + b^2) + 2ab.
16 + 2*8 = 32.
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