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if a3 = 20 and a6=41 for an arithmetic sequence, find a1
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a(6)=a(1)+(6-1)d
a(3)=a(1)+(3-1)d
Subtract:
a(6)-a(3)=3d
41-20=3d
d=7
from which
a(3)=a(1)+(3-1)7
a(1)=20-14=6
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