If a weak acid has a dissociation constant of 6.4 x 10(-6), what is the pH of a solution of this acid in 0.10 molar concentration?

Answer 1

..........HA ==> H^+ + A^-
initial...0.1....0......0
change....-x....+x......+x
final.....0.1-x...+x.....+x

Ka = (H^+)(A^-)/(HA)
Substitute into Ka expression from ICE chart above and solve for (H^+), then convert to pH.