Is this supposed to be a trick question?
sin^2 Ø + cos^2 Ø - 1
= 1 - 1
= 0
the fact that we have a triangle of sides 12 and 5 in a circle has nothing to do with it.
if a triangle with sides 12 unit and 5 unit is inscribed in a circle with BC as diameter, then find the value of sin square theta +cos square theta -1
2 answers
btw, as an aside to your question ...
Any angle subtended by a diameter is a right-angle, so you would have the 5-12-13 right-angled triangle.
the larger of the acute angles is arctan(12/5)
and the smaller is arctan(5/12) ---> appr 22.6°
note:
sin^2 22.6° + cos^2 22.6° - 1
= 1-1 = 0
Any angle subtended by a diameter is a right-angle, so you would have the 5-12-13 right-angled triangle.
the larger of the acute angles is arctan(12/5)
and the smaller is arctan(5/12) ---> appr 22.6°
note:
sin^2 22.6° + cos^2 22.6° - 1
= 1-1 = 0
0 answers