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If a triangle has angle measures 15, 120 and 45, and the length of the side between the 15 and 120 angles is 8, what is the area of the triangle?

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Let A = 15, B = 120 and C = 45 degrees

The side with length 8 is opposite the 45 degree angle. (side c)
sinC/c = sinB/b = sin A/a = 0.08839
b = 9.798
a = 2.928
c = 8.000

Area = (1/2) bc sin A
= 10.14 square length units
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