If a triangle has a leg with length 12 and the hypotenuse is 16, how long is the other leg? If necessary, round to the nearest tenth.

Answer 1

Using the Pythagorean theorem, we can solve for the length of the other leg:

a^2 + b^2 = c^2
(12)^2 + b^2 = (16)^2
144 + b^2 = 256
b^2 = 112
b = √112
b ≈ 10.6

Therefore, the length of the other leg is approximately 10.6.