If a track weighs only 5% more than a car, then the truck weight is blank. Percentage of the car's weight injury. One point five twenty 54 seventy five and negative seventy five.Which one is the answer

1 answer

To determine the weight of the truck in relation to the car, we can set up the following relationship based on the information provided:

Let's assume the weight of the car is \( C \). According to the problem, the truck weighs 5% more than the car, so we can express the weight of the truck \( T \) as:

\[ T = C + 0.05C = 1.05C \]

Now, if you are looking for the percentage difference in weights, we can calculate the percentage that the truck's weight is more than the car's weight:

\[ \text{Percentage increase} = \frac{T - C}{C} \times 100% = \frac{1.05C - C}{C} \times 100% = \frac{0.05C}{C} \times 100% = 5% \]

Based on your options, it appears you are looking for how much greater the truck's weight is compared to the car's weight, which is simply the 5% we derived. However, if you're presented with options "one point five twenty 54 seventy five and negative seventy five" none of these seem to directly correlate with the 5% we've calculated or any straightforward assumption.

If you could clarify or provide a more complete context or set of options, I'd be happy to assist further!