If a tablet contains 129 mg of Mg(OH)2 and 505 mg of CaCO3, how many moles of HCl would theoretically be neutralized?

Answer 1

Mg(OH)2 + 2HCl ==> MgCl2 + 2H2O
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2

mols Mg(OH)2 = 0.129/molar mass = ?
mols CaCl3 = 0.505/molar mass.

?mol Mg(OH)2 x 2 = mols HCl
? mol CaCO3 x 2 = mols HCl
Total mols HCl = sum of the above.