V=10 * 5 * 2.3 = 115 m^3=Vol. of water.
Mass=V*Dw=115m^3 + 1000kg/m^3=115,000kg
F = 115,000kg*9.8N/kg = 1,127,000 N.
If a swimming pool has dimensions; 28.2
5m x 10.0m x 2.30m, when it is full of water, what is the force on the bottom ?
1 answer