Out of a total of 421 people, of both sexes and three classifications of smoking habits, 135 were nonsmoking men. Therefore the probability is 135/421 = 0.3207
This assumes that the sampling group was representative of the larger group of people they may have been drawn from.
If a student is chosen at random, find the probability of getting someone who is a man or a non-smoker. Round your answer to three decimal places.
non regular heavy total
man 135 64 5 204
women 187 21 9 217
total 322 85 14 421
Answer in decimal (round to nearest 3)
Please help me, I've taken more than an hour to figure this problem out! Please guys! Really appreciate it.
5 answers
ops, 0.307 is not in the answer choices.
they are:
0.929
0.798
0.949
0.941
P.S. - Probability of getting a Man OR A Non-Smoker
they are:
0.929
0.798
0.949
0.941
P.S. - Probability of getting a Man OR A Non-Smoker
Need help with this plzzzzzzzzzz
I misread the problem as man AND nonsmoker. You want man OR nonsmoker. Using the same method but more groups from the table, I get
(204 + 187)/421 = 0.929
(204 + 187)/421 = 0.929
Calculate the standard deviation for: 10, 20, 30 to the nearest tenth presuming a sample