If a student has an average exam score between 70 and​ 79, he will earn a grade of C in his algebra course. Suppose he has three exam scores of 77​, 61​, and 81 and that his teacher said the final exam score has twice the weight of the other three exams. What range of scores on the final exam will result in him earning a grade of​ C?

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Part 1
The range of scores on the final exam that will result in him earning a grade of C is
  
enter your response hereless than or equalsxless than or equals
  
enter your response here. ​(Type integers or​ decimals.)

1 answer

To find the range of scores on the final exam that will result in the student earning a grade of C (an average score between 70 and 79), we will first outline the components needed to calculate the average. The final exam has twice the weight of the other exams.

Let's define:

  • \( x \) = final exam score
  • The three exam scores are 77, 61, and 81.

The total contribution of the three exams is \( 77 + 61 + 81 = 219 \).

Since the final exam has twice the weight, it can be considered as contributing a score of \( 2x \).

Now we can set up the average formula:

\[ \text{Average} = \frac{(77 + 61 + 81) + 2x}{3 + 2} = \frac{219 + 2x}{5} \]

To earn a grade of C, the average must be between 70 and 79:

\[ 70 \leq \frac{219 + 2x}{5} \leq 79 \]

Step 1: Solve the lower bound (≥ 70):

\[ 70 \leq \frac{219 + 2x}{5} \]

Multiply both sides by 5:

\[ 350 \leq 219 + 2x \]

Subtract 219 from both sides:

\[ 131 \leq 2x \]

Divide by 2:

\[ 65.5 \leq x \]

Step 2: Solve the upper bound (≤ 79):

\[ \frac{219 + 2x}{5} \leq 79 \]

Multiply both sides by 5:

\[ 219 + 2x \leq 395 \]

Subtract 219 from both sides:

\[ 2x \leq 176 \]

Divide by 2:

\[ x \leq 88 \]

Conclusion:

Combining both results, we find that:

\[ 65.5 \leq x \leq 88 \]

Thus, the range of scores on the final exam that will result in him earning a grade of C is:

\[ \text{Range: } 65.5 \leq x \leq 88 \]