If a student has an average exam score between 70 and​ 79, he will earn a grade of C in his algebra course. Suppose he has three exam scores of 78​, 63​, and 82 and that his teacher said the final exam score has twice the weight of the other three exams. What range of scores on the final exam will result in him earning a grade of​ C?

The range of scores on the final exam that will result in him earning a grade of C is
  
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1 answer

To determine the range of scores on the final exam that would allow the student to earn a grade of C (average exam score between 70 and 79), we first need to account for the weighting of the final exam.

Let \( x \) be the score on the final exam. Since the final exam has twice the weight of the other three exams, we can model the average as follows:

  1. The three exam scores are: 78, 63, and 82.
  2. Their total sum is: \[ 78 + 63 + 82 = 223. \]
  3. The final exam score \( x \) counts as two scores.

Thus, the average score \( A \) can be computed using the following formula:

\[ A = \frac{78 + 63 + 82 + 2x}{3 + 2} = \frac{223 + 2x}{5}. \]

For the student to earn a grade of C, the average score must be between 70 and 79. We can set up two inequalities to find the values of \( x \):

  1. For the lower bound (70): \[ \frac{223 + 2x}{5} \geq 70. \] Multiply both sides by 5: \[ 223 + 2x \geq 350. \] Subtract 223 from both sides: \[ 2x \geq 127. \] Divide both sides by 2: \[ x \geq 63.5. \]

  2. For the upper bound (79): \[ \frac{223 + 2x}{5} \leq 79. \] Multiply both sides by 5: \[ 223 + 2x \leq 395. \] Subtract 223 from both sides: \[ 2x \leq 172. \] Divide both sides by 2: \[ x \leq 86. \]

Combining both results, we find:

\[ 63.5 \leq x \leq 86. \]

Therefore, the range of scores on the final exam that will result in the student earning a grade of C is:

63.5 ≤ x ≤ 86.