If a stone is thrown with velocity 10 m/s. How high will it reach after 10 s. Take g = 10 m/s^2

Question

I want to know if this question is practically possible. I tried to solve this problem and ended up getting the answer in negative. Please help me!!! Afterall time of fall is inversely proportional to g.

Answer 1

You are right about the negative answer.
Assuming the stone is thrown straight up,
d=(10 m/s)(10 s) + (1/2)(-10 m/s^2)(10 s)^2
d= -400 m

It coud be possible if the stone were thrown straight up, over a deep pit. It would mean that the stone was located 400m down into the pit at 10 seconds.

Answer 2

with g=10

the highest it gets is 5 m

at t = 1 s