W = 1/2 kx^2
1st: W = 1/2 k(2^2)
2nd: W - 1/2 k(4^2)
16/4 = 4 => 4x as much
If a spring is compressed 2.0 cm from its equilibrium position and the ncompressed an addition 4.0 cm, how much more work is done in the second compression than in the first?
1 answer