If a solution of HF (Ka = 6.8*10-4) has a pH of 3.42, calculate the total concentration of hydrofluoric acid.

Answer 1

pH = 3.42 = -log(H^+)
(H^+) = 3.8E-4
.........HF ==> H^+ + F^-
equil.(x-3.8E-4).....3.8E-4..3.8E-4

Ka = 6.8E-4 = (H^+)(F^-)/(HF)
Plug in values from the above chart an solve for x

Answer 2

THANX