If a solution of chloride in water is 0.354 M Cl− at 25°C,

Question

and the density of the solution 0.456 g/mL, what is the
molality of Cl− in the solution?

Answer 1

0.354 M = 0.354 mols Cl^-/ L solution.
If the density of the solution is 0.456 g/mL then the solution has a mass of
mass = volume x density = 1000 mL x 0.456 g/mL = 456 g or 0.456 kg.
molality = mols/kg solvent; therefore, molality = m = 0.354/0.456 = ?