consider that T^2 = kr^3
That means that T^2/r^3 is constant
T^2/r^3 = (2T)^2/(xr)^3 = 4T^2/x^3r^3
So, 4/x^3 = 1, and x = ∛4
That is, our small planet's orbital radius is ∛4 times earth's.
If a small planet were discovered whose orbital period was twice that of
Earth, how many times farther from the Sun would this planet be?
1 answer