If a ship leaves port at 9:00 a.m. and sails due north for 3 hours at 12 knots, then turns N 30° E for another hour, how far from port is the ship?

Answer 1

If you make your sketch you will see a cosine law problem.
let the distance from port be k nautical miles
d^2 = 36^2 + 12^2 - 2(12)(36)cos 150°
= ...
d = √...
= ....