Silver carbonate is Ag2CO3. I've rounded here and there and estimated so you must look up atomic masses and redo the math to obtain a more accurate anwer.
1.75 g Ag/108 = approx 0.016 mols Ag atoms.
1/2 that or 0.008 = mols Ag2CO3 molecules.
Then 3x that = mols oxygen since there are 3 atoms O per 1 molecule Ag2CO3.
Then convert mols oxygen to grams. g mols x molar mass
If a sample of silver carbonate contains 1.75 grams of silver [Ag] atoms, calculate the mass (in grams) it contains of oxygen atoms [O].
1 answer
5 answers