Are you sure you copied this problem correctly?
A rug with a perimeter of 17 cm wouldn't be large enough to hold my big toe.
if a rug's perimeter is 17cm and the area is 13cm, what are the reasurments for the length and width?
4 answers
this is copied correctly. the teacher wanted to keep it simple
Your teacher should have stated that the area is 13 cm^2.
If your teacher tried to make it simple, then he/she did not do such a good job.
I did it by algebra and it led to a quadratic equation.
length - x
width - y
2x + 2y = 17
x + y = 8.5
also xy = 13, so y = 13/x
x + 13/x = 8.5
x^2 - 8.5x + 13 = 0
2x^2 - 17x + 26 = 0
(x-2)(2x - 13) = 0
x = 2 or x = 6.5
if x = 2 , then y = 6.5
if x = 6.5, then y = 2
so the "rug" is 2 cm by 6.5 cm, and as Ms Sue noted, probably just big enough to fit into a doll house.
I have a 4th grade "guess" at that answer is rather stretching it.
If your teacher tried to make it simple, then he/she did not do such a good job.
I did it by algebra and it led to a quadratic equation.
length - x
width - y
2x + 2y = 17
x + y = 8.5
also xy = 13, so y = 13/x
x + 13/x = 8.5
x^2 - 8.5x + 13 = 0
2x^2 - 17x + 26 = 0
(x-2)(2x - 13) = 0
x = 2 or x = 6.5
if x = 2 , then y = 6.5
if x = 6.5, then y = 2
so the "rug" is 2 cm by 6.5 cm, and as Ms Sue noted, probably just big enough to fit into a doll house.
I have a 4th grade "guess" at that answer is rather stretching it.
That is not 4th grade homework