1. h=50-4.9*1.6^2
no, you are wrong.
If a rock falls from a height of 50
meters on Earth, the height H (in meters) after x seconds is approximately H(x)=50-4.9x^2
1. What is the height of the rock when x=1.6 seconds?
2. When is the height of the rock 5 meters?
3. When does the rock strike the ground?
I think the first one is 3.03 not sure if I'm right.
4 answers
thank you how do I set the the third question to get the answer.
h is zero when it hits the ground
h=50-4.9t^2
t= sqrt (50-h) / 4.9
h=50-4.9t^2
t= sqrt (50-h) / 4.9
1. 30.4