If a right triangle has a leg with length 12 in. and the hypotenuse is 16 in., the other leg must be approximately [blank] in

11.5
10.6
20
8.6

1 answer

To find the length of the other leg in a right triangle, we can use the Pythagorean theorem, which states:

\[ a^2 + b^2 = c^2 \]

Where:

  • \( a \) and \( b \) are the lengths of the legs,
  • \( c \) is the length of the hypotenuse.

In this case, one leg \( a = 12 \) in and the hypotenuse \( c = 16 \) in. We need to find the length of the other leg \( b \).

Substituting the known values into the theorem gives us:

\[ 12^2 + b^2 = 16^2 \]

Calculating the squares:

\[ 144 + b^2 = 256 \]

Now, subtract 144 from both sides:

\[ b^2 = 256 - 144 \] \[ b^2 = 112 \]

Next, take the square root of both sides to find \( b \):

\[ b = \sqrt{112} \] \[ b \approx 10.583 \]

Thus, the length of the other leg is approximately \( 10.6 \) in.

So, the answer is 10.6 in.