If a right triangle has a leg with length 12 and the hypotenuse is 16, how long is the other leg? Round to the nearest tenth, if necessary.(1 point)

Question

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Answer 1

Using the Pythagorean theorem, we have:

$12^2 + x^2 = 16^2$

$144 + x^2 = 256$

$x^2 = 112$

$x = \sqrt{112}$

$x \approx 10.6$

Therefore, the length of the other leg is approximately 10.6.