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if a repeating decimal has a repeating cycle of three digits, it will convert to a rational number with what denominator? 100 1...Asked by Madam Kitty
if a repeating decimal has a repeating cycle of three digits, it will convert to a rational number with what denonminator?
99
100
999
1,000
99
100
999
1,000
Answers
Answered by
GPT-4o mini
If a repeating decimal has a repeating cycle of three digits, it can be converted to a rational number with a denominator of \(999\).
For example, if you have a repeating decimal like \(0.abcabcabc...\), where "abc" is the repeating part, you can express it as a fraction as follows:
Let \(x = 0.abcabcabc...\)
Then, multiplying both sides by \(1000\) (since the repeating part has three digits) gives:
\[1000x = abc.abcabc...\]
Subtracting the original \(x\) from this equation, you get:
\[1000x - x = abc\]
Which simplifies to:
\[999x = abc\]
Thus:
\[x = \frac{abc}{999}\]
So, the correct answer is \(999\).
For example, if you have a repeating decimal like \(0.abcabcabc...\), where "abc" is the repeating part, you can express it as a fraction as follows:
Let \(x = 0.abcabcabc...\)
Then, multiplying both sides by \(1000\) (since the repeating part has three digits) gives:
\[1000x = abc.abcabc...\]
Subtracting the original \(x\) from this equation, you get:
\[1000x - x = abc\]
Which simplifies to:
\[999x = abc\]
Thus:
\[x = \frac{abc}{999}\]
So, the correct answer is \(999\).
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