If a repeating decimal has a repeating cycle of three digits, it can be converted to a rational number with a denominator of \(999\).
For example, if you have a repeating decimal like \(0.abcabcabc...\), where "abc" is the repeating part, you can express it as a fraction as follows:
Let \(x = 0.abcabcabc...\)
Then, multiplying both sides by \(1000\) (since the repeating part has three digits) gives:
\[1000x = abc.abcabc...\]
Subtracting the original \(x\) from this equation, you get:
\[1000x - x = abc\]
Which simplifies to:
\[999x = abc\]
Thus:
\[x = \frac{abc}{999}\]
So, the correct answer is \(999\).