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if a repeating decimal has a repeating cycle of three digits, it will convert to a rational number with what denominator? 100 1...Question
If a repeating decimal has a repeating cycle of three digits, it will convert to a rational number with what denominator?
A. 999
B. 100
C. 99
D. 1,000
A. 999
B. 100
C. 99
D. 1,000
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Answered by
GPT-4o mini
A repeating decimal with a repeating cycle of three digits can be converted to a rational number with a denominator of 999.
To understand why, consider a repeating decimal like \( 0.\overline{abc} \) where \( abc \) represents the three digits that repeat.
When you express this repeating decimal as a fraction, it can be done by setting:
\[
x = 0.\overline{abc}
\]
Multiplying both sides by \( 1000 \) (since there are three repeating digits), you have:
\[
1000x = abc.\overline{abc}
\]
Now, subtract the first equation from the second:
\[
1000x - x = abc.\overline{abc} - 0.\overline{abc}
\]
This simplifies to:
\[
999x = abc
\]
Thus, we have:
\[
x = \frac{abc}{999}
\]
So, the denominator of the rational number representation of a repeating decimal with a repeating cycle of three digits is \( 999 \).
Therefore, the correct answer is **A. 999**.
To understand why, consider a repeating decimal like \( 0.\overline{abc} \) where \( abc \) represents the three digits that repeat.
When you express this repeating decimal as a fraction, it can be done by setting:
\[
x = 0.\overline{abc}
\]
Multiplying both sides by \( 1000 \) (since there are three repeating digits), you have:
\[
1000x = abc.\overline{abc}
\]
Now, subtract the first equation from the second:
\[
1000x - x = abc.\overline{abc} - 0.\overline{abc}
\]
This simplifies to:
\[
999x = abc
\]
Thus, we have:
\[
x = \frac{abc}{999}
\]
So, the denominator of the rational number representation of a repeating decimal with a repeating cycle of three digits is \( 999 \).
Therefore, the correct answer is **A. 999**.
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