well,
x^2-2x-80 = (x-10)(x+8)
so, ...
if a rectangular paintings area is given by the polynomial x^2-2x-80 what are the possible dimensions of the painting.
3 answers
Solve by factoring out the polynomial, and you would get:
(x+8)(x-10). Set those equal to 0, and x will equal 10 and -8.
Thus, the answer is that the possible dimensions 10 by 8 (you can't have negative dimensions, so change -8 to positive).
Hope this helps!
(x+8)(x-10). Set those equal to 0, and x will equal 10 and -8.
Thus, the answer is that the possible dimensions 10 by 8 (you can't have negative dimensions, so change -8 to positive).
Hope this helps!
why would you set either factor to zero? As long as x > 10 you can satisfy the conditions of the problem.