If a quantity of gas in a piston cylinder has a volume of 0.9 m3 and is initially at room temperature (30°C) and is heated in an isobaric (constant-pressure) process, what will be the temperature of the gas in degrees Celsius when it has expanded to a volume of 1.2 m3?

Answer 1

assuming the gas is ideal, we can use Charles' Law:
V1/T1 = V2/T2
where
V1 = initial volume
V2 = final volume
T1 = initial temperature (in Kelvin)
T2 = final temperature (in Kelvin)
we first convert the given temp to Kelvin:
T1 = 30 + 273.15 = 303.15 K
substituting,
V1/T1 = V2/T2
0.9 / 303.15 = 1.2 / (T2)
T2 = 1.2*303.15/0.9
T2 = 404.2 K or 131.05 deg C

hope this helps~ :)