If a quadratic has a vertex at (-2,2) and passes through (-1,0) what is its equation in standard form?

Question

A. y = -2(x-2)^2 + 2
B. y = -2(x+2)^2 + 2
C. y = -(x+2)^2 - 2
D. y = (x+2)^2 + 2

Is the answer B?

Answer 1

of course, B