Asked by Rick
If a projectial is fired at such an angle that the vertical componet of its velocity is 49m/s. The horizonal componet of its velocity is 61m/s, then how long will the projectia stay in the air? What distance will it travel? And what is the inital speed?
Answers
Answered by
bobpursley
Your teacher is pretty easy.
vertical component: solve for time in air.
hf=ho+vyi*t- 4.9t^2 vyi=49, hf=ho=0
distance traveled:
distance= 61*timeinair
Initial speed= sqrt(49^2+61^1)
vertical component: solve for time in air.
hf=ho+vyi*t- 4.9t^2 vyi=49, hf=ho=0
distance traveled:
distance= 61*timeinair
Initial speed= sqrt(49^2+61^1)
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