If a projectial is fired at such an angle that the vertical componet of its velocity is 49m/s. The horizonal componet of its velocity is 61m/s, then how long will the projectia stay in the air? What distance will it travel? And what is the inital speed?

Answer 1

Your teacher is pretty easy.

vertical component: solve for time in air.

hf=ho+vyi*t- 4.9t^2 vyi=49, hf=ho=0

distance traveled:
distance= 61*timeinair

Initial speed= sqrt(49^2+61^1)