V = 49t^2,
t^2 = V/49,
t^2 = 20 / 49 = 0.408s.
If a pro basketball player has a vertical leap of about 20in., what is his hang time?
Use the hang time function v=49t^2
1 answer
Use the hang time function v=49t^2
1 answer
0 answers
4 answers
1 answer
11 answers