consider the two letters as one item. Then there are
26^2 * 10^4 possible plates.
The letters and digits can be rearranged in 5! ways, so there are
26^2 * 10^4 * 5! different plates with the letters together.
There are 36^6 possible plates in all, so our probability is
(26^2 * 10^4 * 5!)/36^6 = 0.37266
If a plate of car consists of a two letter and four digits and one car is chosen at random, then find the probability that the car has the letter together
2 answers
actually, that's not quite right, since I did not allow for the fact that if a character is repeated, the plate count has to be reduced. See whet you can do with that.