If a mothball (C10H8) has a mass of 1.32 grams, how many naphthalene molecules does it contain?

Question

If I'm right just multiply 1.32g by 6.022*10^23 and the answer is 7.949*10^23 molecules.
Is this right?

Answer 1

Close but no cigar.
It is not a gram that contain 6.022E23 but a MOLE that contains 6.022E23.
So convert that 1.32 g to mols.
mols = grams/molar mass = ?.
Then that many mols x 6.022E23 molecules/mol = # molecules of C10H8..

Answer 2

Okay,
so 1.32/128.164=.0103
0.0103*6.022*10^23=6.2*10^21 molecules
?

Answer 3

Yes it's correct