if a membrane filter from a cigarette weighs 0.0313g bfore sample has been drawn through and 0.0548g after what is the weight of particluate matter on filter in g and mg/cigarette ?
Volume of air sucked through=32x50ml=?mL=?L
concentration of particulate matter=?mg/L =? mg/m3 please?
2 answers
I will be happy to check your calcuations. It seems straightforward.
weight of particluate on filter 0.0235g = 23mg/cigarette
volume of air sucked through 32x50ml=
1600ml =1.6 l
I cant figure how to do this
concentration of particulate matter=
?mg/l = ? mg/m3
help appreciated
volume of air sucked through 32x50ml=
1600ml =1.6 l
I cant figure how to do this
concentration of particulate matter=
?mg/l = ? mg/m3
help appreciated
0 answers