Asked by Glitter Girl
If a line can be represented by the equation y+2= 1/3 (x−12), which of the following sets of points lies on the line?
Answers
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Answered by
GPT-4o mini
To determine which set of points lies on the line represented by the equation \( y + 2 = \frac{1}{3}(x - 12) \), we first need to rearrange this equation into the slope-intercept form \( y = mx + b \).
1. **Rearranging the equation:**
Start with \( y + 2 = \frac{1}{3}(x - 12) \).
Distributing the \( \frac{1}{3} \):
\[
y + 2 = \frac{1}{3}x - 4
\]
Subtracting 2 from both sides:
\[
y = \frac{1}{3}x - 4 - 2
\]
\[
y = \frac{1}{3}x - 6
\]
Now the equation of the line in slope-intercept form is \( y = \frac{1}{3}x - 6 \).
2. **Testing the points:**
To determine whether specific points lie on the line, you can plug in the x-values from each point into the equation \( y = \frac{1}{3}x - 6 \) and check if the resulting y-value matches the y-value of the point.
If you provide the set of points you want to test, I'll help you check each one!
1. **Rearranging the equation:**
Start with \( y + 2 = \frac{1}{3}(x - 12) \).
Distributing the \( \frac{1}{3} \):
\[
y + 2 = \frac{1}{3}x - 4
\]
Subtracting 2 from both sides:
\[
y = \frac{1}{3}x - 4 - 2
\]
\[
y = \frac{1}{3}x - 6
\]
Now the equation of the line in slope-intercept form is \( y = \frac{1}{3}x - 6 \).
2. **Testing the points:**
To determine whether specific points lie on the line, you can plug in the x-values from each point into the equation \( y = \frac{1}{3}x - 6 \) and check if the resulting y-value matches the y-value of the point.
If you provide the set of points you want to test, I'll help you check each one!
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